I don't think i've been so confused ever, how do I solve this using long division?
1 answer:
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<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) p(getting 2 good coils for second selection)
p(first selection) = p(second selection) =
Hence, p(getting 2 good coil for two selection) =