Answer:
Part A:
Part B:
and 
Step-by-step explanation:
Part A:
The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:
Using the value of y from the first equation in the second one, we have:
Part B:
If he shoots a total of ten targets, we can write the equation:
Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:
If we subtract the second equation by two times the first one, we have:
⇒
Answer:
y=2x+5 is the answer ALSO CAN WE TALK ABOUT THE FACT THAT MOO975 IS ON THREE QUESTIONS AT THE SAME TIME
Step-by-step explanation:
Answer:
We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz
Step-by-step explanation:
Mean = 3.2 oz, sd = 0.13 oz
Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303
Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz
Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz
You are missing part of the question
Answer:
All options
Step-by-step explanation:
If two coins are flipped, there are following possibilities
1. Both coins show heads
2. First coin shows heads and second shows tails
3. First coin shows tails and second shows heads
4. Both coins show tails
Let H denote heads and T denote tails
Then the sample space can be translated from the above events as:
Sample Space for Flipping Two Coins = {HH, HT, TH, TT}
which means that all the options are correct ..
