express the area A of an isosceles right triangle as a function of the length s of one of its two equal sides.
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Answer:
The length of a side of the original field = 7 m.
Step-by-step explanation:
Here, the initial field is in form of a square.
Let us assume the side of the original square field = k meters
Now, the new length of the field = ( k + 3) m
The new width of the field = ( k + 2) m
So, the new field is now a rectangle with area = 90 sq. m
AREA OF A RECTANGLE = LENGTH x WIDTH
Here, the area of the new field = New length x new width
= ( k + 3) x ( k + 2)
⇒ either (k +12) = 0 ⇒ k = -12
or, ( k-7) = 0 ⇒ k = 7
But, here k = SIDE OF A FIELD, and it CANNOT be negative.
⇒ k = 7
Hence, the length of a side of the original field = 7 m.