Ask question

Ask question

All categories

Yakvenalex [24]

3 years ago

5

If an investor possesses a portfolio heavily concentrated in futures, a financial advisor would most likely suggest adding which

conservative investment to diversify the portfolio?
A. Certificate of Deposit
B. Futures
C. Mutual Funds
D. Stocks

Advanced Placement (AP)

1 answer:

elena-s [515]3 years ago

4 0

A Certificate of deposit (CD) is a conservative investment because it is very unlikely that the money will be lost (low risk)

You might be interested in

Which of the following statements is FALSE? A. Summarizing involves presenting the essential points of information. B. Paraphras

pashok25 [27]

Answer:

D. If no author can be found on a website, you do not need to cite the website as a source.

6 0

3 years ago

Which influence is stronger—religion's influence on the environment or the environment's influence on religion?

Over [174]

Environment impact on religion

8 0

4 years ago

Read 2 more answers

What can you tell me about THEME? What is it? what is its purpose?

vladimir1956 [14]

Answer:

theme gives readers better understanding of main characters conflict , experiences discoveries

5 0

3 years ago

2. Find the solution of each differential equation. (a) y/2y-8y = 0 (b) 25y/- 20y + 4y = 0 (c) y + 2y + 2y = 0 2. Find the solut

jek_recluse [69]

Each of these ODEs is linear and homogeneous with constant coefficients, so we only need to find the roots to their respective characteristic equations.

(a) The characteristic equation for

$y'' - 2y' - 8y = 0$

is

$r^2 - 2r - 8 = (r - 4) (r + 2) = 0$

which arises from the ansatz $y = e^{rx}$ .

The characteristic roots are $r=4$ and $r=-2$ . Then the general solution is

$\boxed{y = C_1 e^{4x} + C_2 e^{-2x}}$

where $C_1,C_2$ are arbitrary constants.

(b) The characteristic equation here is

$25r^2 - 20r + 4 = (5r - 2)^2 = 0$

with a root at $r=\frac25$ of multiplicity 2. Then the general solution is

$\boxed{y = C_1 e^{2/5\,x} + C_2 x e^{2/5\,x}}$

(c) The characteristic equation is

$r^2 + 2r + 2 = (r + 1)^2 + 1 = 0$

with roots at $r = -1 \pm i$ , where $i=\sqrt{-1}$ . Then the general solution is

$y = C_1 e^{(-1+i)x} + C_2 e^{(-1-i)x}$

Recall Euler's identity,

$e^{ix} = \cos(x) + i \sin(x)$

Then we can rewrite the solution as

$y = C_1 e^{-x} (\cos(x) + i \sin(x)) + C_2 e^{-x} (\cos(x) - i \sin(x))$

or even more simply as

$\boxed{y = C_1 e^{-x} \cos(x) + C_2 e^{-x} \sin(x)}$

3 0

2 years ago

Who whats to talk ???

galina1969 [7]

Answer:

me

Explanation:

5 0

3 years ago

Read 2 more answers