Answer:
Jess used 40 blocks in total.
Step-by-step explanation:
First stack: 8 blocks
Second stack: First stack + 4 = 8 + 4 = 12 blocks
Third stack: Second stack + 8 = 12 + 8 = 20 blocks
Total number of blocks: First stack + Second stack + Third stack = 8 + 12 + 20 = 40 blocks
Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
Least value:16
Median:26
Greatest value:34
Step-by-step explanation:
Bus A leave depot at = 3pm
Bus B leave depot at = 3 pm
both leave depot at 3 pm so
Bus A complete its route in25 mins
Bus A reach at his point at 3:25 pm
Bus B complete its route in 30 mins
Bus B reach at his point at 3:30 pm
So
If the buses go back to depot it will take 25 mins so Bus A reach back at depot at 3:50 pm
Bus B at 4:00 pm
Answer:
Leah: 54km/h
Deborah: 50 km/h
Step-by-step explanation:
250+4x=270
4x=20
x=5
both drove 5 hours
Deborah:
250/5=50km/h
Leah:
270/5=54km/h
