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Sidana [21]
3 years ago
14

What the slope and y intercept ? and how did you find it ?

Mathematics
1 answer:
EastWind [94]3 years ago
7 0

Answer:

Slope: m=4

y-intercept: b=-1

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

The slope can be found with the following formula:

m=\frac{y_2-y_1}{x_2-x_1}

In this case you can say that:

y_2=-5\\y_1=11\\\\x_2=-1\\x_1=3

Knowing this values you can substitute them into the formula and then evaluate, in order to find the slope. This is:

m=\frac{-5-11}{-1-3}\\\\m=\frac{-16}{-4}\\\\m=4

By definition, the line intersects the y-axis when the value of "x" is 0.

Notice in the table that when x=0, y=-1

Therefore, the y-intercept is:

b=-1

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the equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contain
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Answer:

The required equation is y=-\frac{1}{3}x+2.

Step-by-step explanation:

The equation of line cd is

y=3x-3

Slope intercept form of a line is

y=mx+b

Where, m is slope and b is y-intercept.

Slope of line cd is 3.

The product of slopes of two perpendicular lines is -1.

m_1\times m_2=-1

3\times m_2=-1

m_2=-\frac{1}{3}

Therefore slope of perpendicular line is -\frac{1}{3}.

Point slope form of a line is

y-y_1=m(x-x_1)

Slope of perpendicular line is -\frac{1}{3} and line passing through the point (3,1).

y-1=-\frac{1}{3}(x-3)

y=-\frac{1}{3}x+1+1

y=-\frac{1}{3}x+2

Therefore the required equation is y=-\frac{1}{3}x+2.

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