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3 years ago

6

Please help. ASAP. PLEASE HELP Question : Write function for this. Thanks.

1 answer:

Irina18 [472]3 years ago

5 0

It's a modification of sine function.

$y = \sin(x)$ - the first picture.

The values of y are in <-2, 2>. Therefore we have

$y = 2\sin(x)$ - the second picture.

The zeros of the function on the graph are 0, 2, 4, 6, ... → 2k, k ∈ Z

We know. The zeros of a sine are 0, π, 2π, 3π, ... → kπ, k ∈ Z

Therefore we have the equation:

$2ka=k\pi$ <em>divide both sides by 2k</em>

$a=\dfrac{\pi}{2}$

Therefore your answer:

$\boxed{f(x)=2\sin\left(\dfrac{\pi}{2}x\right)}$

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When will these two lines intersect <br>C. y=-2x +3<br>y = x

Andrej [43]

Answer:

The intersection point of the given lines is (1,1).

Step-by-step explanation:

Here, the given equations are:

y = - 2 x + 3

y = x

Substitute y = x in the first equation,

y = -2 x + 3 becomes y = -2 (y) + 3

or, y + 2 y = 3

or, 3 y = 3 ⇒ y = 3/3 = 1

⇒ y = 1

Now, as x = y ⇒ x = 1

Hence, the intersection points of the given lines is (1,1).

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castortr0y [4]

Answer:

$\frac{49}{4}$

Step-by-step explanation:

Convert each to a improper fraction

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Find the value of the power. (2/3)3

Andreyy89

Answer:

The value is 27

Step-by-step explanation:

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3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

3 years ago