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3 years ago

What’s the square root of 48/81?

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

7 0

4 square root of 3 over 9

spayn [35]3 years ago

4 0

Approximately .769800359

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Write the equation of the perpendicular bisector of AB if A(-6, -4) and B (2,0).

valkas [14]

Answer:

Step-by-step explanation:

Long way:

Find the midpoint (M) of AB, find the slope(m) of the line AB, then find the equation of the line through M with slope -1/m, which is the perpendicular bisector of AB.

Short way:

The perpendicular bisector of (x₁,y₁) and (x₂,y₂): 2(x₂-x₁)x + 2(y₂-y₁)y = x₂²-x₁²+y₂²-y₁².

Here this is 2(1-(-4))x + 2(6-4)y = 1²-(-4)²+6²-4² which is 10x + 4y = 5.

4 0

3 years ago

Two hikers, Charles and Maria, begin at the same location and travel in perpendicular directions. Charles travels due north at a

attashe74 [19]

Answer:

d(L)/dt = 9,43 miles per hour

Step-by-step explanation:

As Charles and Maria travel in perpendicular directions, these directions could be considered as two legs ( x and y ) of a right triangle and distance (L) between them as the hypotenuse, therefore, according to Pythagoras theorem

L² = x² + y²

And as all ( L , x , and y ) are function of time, we apply differentiation in both sides of the equation to get

2* L d(L)/dt = 2*x*d(x)/dt + 2*y*d(y)/dt (1)

In equation (1) we know:

d(x)/dt = 8 miles/per hour ( Maria )

d(y)/dt = 5 miles /per hour (Charles)

In 3 hours time Maria has travel 3*8 = 24 miles

And Charles 5*3 = 15 miles

Then at that time L is equal to

L = √ 24² + 15² ⇒ L = √ 576 + 225 ⇒ L = √801 ⇒ L =28,30 miles

Then plugging these values in equation (1)

2* L d(L)/dt = 2*x*d(x)/dt + 2*y*d(y)/dt

2* 28.30 * d(L)/dt = 2*24*8 + 2* 15*5

56.6 *d(L)/dt = 384 + 150

d(L)/dt = 534/56,6

d(L)/dt = 9,43 miles per hour

4 0

3 years ago

Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation

Virty [35]

Answer:

Solve v + 6 = 5v − 2 to find the value of v.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Locating Zeros of Polynomial Function:<br>Approximate the real zeros to the nearest tenth

solmaris [256]

we are given

$f(x)=2x^4-x^3+x-2$

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

At x=1:

$f(1)=2(1)^4-(1)^3+(1)-2$

$f(1)=0$

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

$f(-2)=2(-2)^4-(-2)^3+(-2)-2$

$f(-2)=36$

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

$f(-1)=2(-1)^4-(-1)^3+(-1)-2$

$f(-1)=0$

At x=0:

$f(0)=2(0)^4-(0)^3+(0)-2$

$f(0)=-2$

so, this is FALSE

5 0

3 years ago

[x + 3y = -4] [2x + 6y = 5]

stealth61 [152]

Step-by-step explanation:

x+3y=-4(eqn1)

x=-4-3y

from (eqn 2)

2(-4-3y)+6y=5

-8-6y+6y=5

y=5+8=13.

y=13

from eqn 1

x+3(13)=-4

x+39=-4

x=-4-39

x=-43.

3 0

3 years ago