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sveta [45]
3 years ago
5

5.2 The Right Height: True or Not?

Mathematics
2 answers:
Anna71 [15]3 years ago
8 0
The answer is G I think soooooo
Serhud [2]3 years ago
7 0

Answer:

g

Step-by-step explanation:

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Tia owns a fruit shop and is selling a fresh lot of apples and oranges. She wants the ratio of apples to oranges sold to be 3 to
prisoha [69]

i have no idea how many apples should she sell

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3 years ago
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Find the value of y.<br> m&lt;1 = 3y + 6
Rufina [12.5K]

Step-by-step explanation:

m > 1 = 3y  + 6\\  \frac{m >  -1 - 6}{3}  =  \frac{3y}{3}  \\ y =  \frac{m >  - 5}{3}

7 0
3 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
3 years ago
Name the marked angle in 2 different ways.
stiv31 [10]

Answer:

acute is one of the i hope this helps

6 0
3 years ago
What is the solution to x-4y=-5 and -x+6y=7
Triss [41]
<span>  x - 4y = -5
-x + 6y = 7
---------------add
       2y = 2
         y = 1

</span>     x - 4y = -5 
  x - 4(1) = -5 
      x - 4 = -5
           x = -1

answer
x = -1 and y = 1
8 0
3 years ago
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