Question

Find the area of the shaded region. Round to the nearest tenth.

Answer 1

(shaded area) = (area of circle section 360-130 degrees) + (isosceles triangle)

(section area 230 degrees) = $\frac{230^\circ}{360^\circ}\pi r^2= 0.6389\cdot 3.1416\cdot 123.21 m^2 = 247.3m^2$

(triangle area) = $\frac{1}{2}a\cdot b\cdot\sin 130^\circ = \frac{1}{2}11.1^2 m^2\cdot\sin 130^\circ=47.19m^2$

(Total area) = 247.3 + 47.2 = 294.5 m^2