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evablogger [386]

4 years ago

15

Greg has a bag that contains 25 colored tiles. Of all the tiles in this bag, 10 are blue. Suppose another bag contains 250 colo

red tiles. Of all the tiles in this bag, 75 are blue. From which bag is Greg less likely to pick a blue tile? Explain.

1 answer:

Sergio [31]4 years ago

6 0

Answer:

he is less likely to pick a blue tile in the second bag

Step-by-step explanation:

divide 10 by 25 which will give you 40%

divide 75 by 250 which will give you 30%

this makes it less likely for Greg to pick blue from the second bag, as the first bag has a higher percentage chance

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When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

3 years ago

Justin buys 12 pencils for $0.56. He pays with a $10 bill. How much charge will he recieve?

Andreyy89

I don't imagine you could divide with this since the answer would lead to 0.04 but if so i'm an idiot.

The way i would do it is 12 x 0.56 which makes 6.72. (it just makes sense?)

So for the 0.04 he would get back 9.96

The 6.72 he would get back 3.28

Sorry i considered the possibilities.

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4 years ago

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Quadrilateral RSTQ is a parallelogram.

Ket [755]

Answer:

$\angle T \cong \angle R\\\angle S \cong \angle Q$

Step-by-step explanation:

According to the Parallelogram definition, every Parallelogram have a pair of congruent sides. In this case, Namely $\overline{RS} \cong \overline{TQ}$ and $\overline{QR} \cong \overline{TS}$

(not listed as an option)

And the opposite angles are congruent too.

So

$\angle T \cong \angle R\\\angle S \cong \angle Q$

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3 years ago