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Ad libitum [116K]
3 years ago
13

Refer to the exhibit. An administrator is examining the message in a syslog server. What can be determined from the message? Thi

s is a notification message for a normal but significant condition. This is an error message for which warning conditions exist. This is an error message that indicates the system is unusable. This is an alert message for which immediate action is needed.
Computers and Technology
2 answers:
ad-work [718]3 years ago
8 0

Answer:

This is a notification message for a normal but significant condition

Explanation:

Syslog represents the standard for logging message, it sends messages through UDP port 514. Familiar syslog facilities includes IP, OSPF protocols, etc. The messages from syslog are both about facility and level.

A syslog server is a means through which network devices sends messages about events into a logging server which is called syslog server. Since a syslog protocol supports so many devices, it can also be used to log a good number of events.

3241004551 [841]3 years ago
5 0

Answer:

A) This is a notification message for a normal but significant condition

Explanation:

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Name the contributory components that are considered when determining an E/M code; they are not considered key components:
Vika [28.1K]

Answer:

time

Explanation:

E/M code is known as the evaluation and management code. The E&M code may be defined as the medical coding system which supports the medical billing process.  Every new patient is assigned a E/M code. The components that are not considered for determining the E/M code are coordination of care, the counselling, time and the nature of presenting problem.

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3 years ago
Write the definition of a function divide that takes four arguments and returns no value . The first two arguments are of type i
Nastasia [14]

Answer:

#include <iostream>

using namespace std;

void divide(int numerator, int denominator, int *quotient, int *remainder)

{

*quotient = (int)(numerator / denominator);

*remainder = numerator % denominator;

}

int main()

{

int num = 42, den = 5, quotient=0, remainder=0;

divide(num, den, &quotient, &remainder);

 

return 0;

}

Explanation:

The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.

To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.

Thanks! :)

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3 years ago
HI PLZ HELP 11 POINTS!!!
bonufazy [111]

Probably gonna wanna determine the table title first

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