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zavuch27 [327]
3 years ago
9

A plane lamina with constant density p(x, y) = p occupies a region in the xy-plane bounded by a simple closed path C. Show that

its moments of inertia about the axes areIx=−p/3∮cy3dx,Iy=p/3∮cx3dy

Mathematics
1 answer:
stira [4]3 years ago
8 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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The volume of water that goes into the hose is the same as the volume of water that comes out the nozzle. This means the velocity is inversely proportional to the area. The area is proportional to the square of the diameter.

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Nozzle velocity = 3^2 * entering velocity
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Carrie filled her watering can with 5 liters
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Answer:The answer is D 3,500 milliliters.

Step-by-step explanation:

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How many students got eight or more answers correct?
slamgirl [31]

Answer:

9

Step-by-step explanation:

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Read 2 more answers
Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)
ANEK [815]
1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
y = 16/2 = 8  
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
 3. Just a right triangle with both legs of known length. Use the Pythagorean theorem 
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
6*sqrt(2) = x 
x is approximately 8.485281374  
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem. 
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8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem. 
x = 2y 
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y^2 = (2y)^2 - (22.5*sqrt(3))^2 
y^2 = 4y^2 - 1518.75 
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y^2 = 506.25 = 2025/4 
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y = 22.5
 x = 2*y = 2*22.5 = 45  
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x = sqrt(16^2 + 30^2) = sqrt(256 + 900) = sqrt(1156) = 34  
10. Another right triangle, another use of the Pythagorean theorem. 
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3 years ago
7 times 29 using area models
drek231 [11]

Answer:

949

Step-by-step explanation:

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