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zavuch27 [327]
3 years ago
9

A plane lamina with constant density p(x, y) = p occupies a region in the xy-plane bounded by a simple closed path C. Show that

its moments of inertia about the axes areIx=−p/3∮cy3dx,Iy=p/3∮cx3dy

Mathematics
1 answer:
stira [4]3 years ago
8 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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Answer:

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Step-by-step explanation:

well the triangles are congruent so that equation has to equal 61, so set it equal to 61, once you do that subtract 10 with 61 giving you 51, then divide 3 with 51 and you get 17

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Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

  • Quadrant 1: Both positive.
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  • Quadrant 3: Both negative.
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Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

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5x + 3y = 7<br> 4x + 5y = 3<br> How do I solve
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Answer:

9x+8y

Step-by-step explanation:

first you would take your liked terms and combine them.

1. 5x+4x=9x

2. 3y+5y=8y

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