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Jet001 [13]
3 years ago
5

What is the Value of -5+2/3 A) 17/3 B) -13/3 C) 13/3 D) -17/3

Mathematics
2 answers:
Mama L [17]3 years ago
7 0
-5+2/3
= -5x 3
=-15+2/3
final answer =-13/3 > B
zysi [14]3 years ago
6 0
Question -5+2/3
= -5*3
=13/3 so B is the answer
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At a recent computer convention, Pomie Lau demonstrated new software to potential customers. She was paid $15 each for the first
saul85 [17]
Answer= $185.00

Commission=15(10)+2(17.50)
Commission=150+35.00
Commission=$185.00

6 0
3 years ago
The board of examiners that administers the real estate broker's examination in a certain state found that the mean score on the
Goshia [24]

Answer:

The passing score is 645.2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 553, \sigma = 72

If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 553}{72}

X - 553 = 1.28*72

X = 645.2

The passing score is 645.2

6 0
3 years ago
Does anyone have any offers for my frost fury?
eimsori [14]
Thanks for the point I appreciate it
3 0
3 years ago
Blank +710=850 can you figure it out
DaniilM [7]
The answer would be 140 because if you subtract 710 from 850 you would get 140.
7 0
3 years ago
Read 2 more answers
Given that y(t)=c1e4t+c2e−4ty(t)=c1e4t+c2e−4t is a solution to the differential equation y′′−16y=0y′′−16y=0, where c1c1 and c2c2
tekilochka [14]

Solution :- Given differential equation

y′′−16y=0

 So the characteristic equation will be

r^{2} -16=0 ⇒r^{2} =16 ⇒[tex]r_{1}=4   \\or \\ r_{2}=-4

so, the  required  function will be

y=c_{1}e^{r_{1}t}+c_{1}e^{r_{2}t}

⇒ y=c_{1}e^{4t}+c_{1}e^{-4t} ia solution of the  given differential equation  

where c_{1} \\and \\c_{2} are constants.

4 0
3 years ago
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