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4 years ago

I need help u guys plzz?

Mathematics

1 answer:

Slav-nsk [51]4 years ago

6 0

Answer:

Step-by-step explanation:

10!/(10-2)!

n!=n(n-1)!

10•9•8!/(10-2)!

10•9•8!/8!

The 8! cancels out and you're left with 10•9

So, your answer is 90

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Solve: 9 + 2 - 10x = 1 - 10x

nevsk [136]

Answer:

0 = -10

Step-by-step explanation:

add 9+2=11

11-10=1-10x rearange terms

-10x+11=1-10x subtract 11 from both sides

−10+11−11=−10+1−1

-10x=-10x-10 add 10 to both sides

−10+10=−10−10+10 simplify cause you subtracts 10 from each side and your left with

0=-10

3 0

3 years ago

Read 2 more answers

Kevin has $1427 in a savings account. His brother, Harley has saved an amount with a 4 that is 1/10 the value of the 4 in Kevin'

Paul [167]

I'm guessing 400$????

3 0

3 years ago

Increase £64 by 70%??????

olya-2409 [2.1K]

I'm not sure if you used the euro sign accidentally or what but this is how to increase 64 by 70%

divide 64 by 10.
6.40
then multiply it by 7.
44.80
then add 44.8 to your original number. (64)
the answer is:
108.8

If you did put that sign there purposely and if it means something then I don't know if it matters or if this is right.

8 0

3 years ago

What is the value of the expression 5x − y when x = 3 and y = 1? 14 10 7 0

12345 [234]

5x-y
=5(3)-1
=15-1
=14

Therefore, the answer is 14.

5 0

3 years ago

Need some help with indefinite integrals pleasee

goldenfox [79]

Observe that $(x^2+2x+2)'=2x+2$ .

You have that $\int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2$ .

To compute $I_1$ you set $y=x^2+2x+2$ , so $dy=2x+2\; dx$ . Therefore, $I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2)$ .

For $I_2$ observe that $x^2+2x+2=(x+1)^2+1$ . Let $y=x+1$ . Then $dy=dx$ and $I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1)$ .

So, $\int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c$ .

8 0

4 years ago