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julia-pushkina [17]
3 years ago
8

Which inequality can be used to represent this problem? pleaseeeee help

Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer

Option ( C )  is correct i.e 3.5x+6 ≤ 85 .

Reason

As given in the question

x represented the pounds of propane delivered .

As given

Propane costs $3.50 per hundred pounds .

there is a $6 monthly delivery fee.

A family has budgeted $85 for their propane this month.

Than the equation becomes

3.5x+6 ≤ 85

Therefore option (C) is correct .

Hence proved


 

     

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I need help pls <br><br> I WILL GIVE BRAINLIEST <br> Pls help
uranmaximum [27]

Answer:

1. The square root of 100

2.c=27.11

d=13.96

e=12.6

<u>Step</u><u> </u><u>by</u><u> </u><u>step</u><u> </u><u>explanation</u><u>:</u><u> </u>

1. 2×50=100 the geometric mean is the square root of 100

2. The diagram is made up of three right angled triangles the big outer one and two triangles inside the big one thus we can use the pythagorean theorem to come up with expressions which will help us in solving the unknown parts as below.

c²=30²-d²

c²=e²+24²

d²=e²+6²

both the following add up to c² meaning they are equal:

c²=30²-d²

c²=e²+24²

thus

30²-d²=e²+24²

I want to remain with d² only thus;

30²-24²-e²=d²

900-576=324 (squareroot of 324=18) so

d²=18²-e² and d²=e²+6²

both the above add up to d² meaning they are equal thus;

18²-e²=e²+6²

18²-6²=e²+e²

324-36=2e²

318=2e²

159=e²

e=12.61

<em>Thus</em><em> </em><em>d</em><em>²</em><em>=</em><em>e</em><em>²</em><em>+</em><em>6</em><em>²</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>2</em><em>.</em><em>6</em><em>1</em><em>²</em><em>+</em><em>6</em><em>²</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>5</em><em>9</em><em>+</em><em>3</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>9</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>9</em><em>6</em>

<em>c</em><em>²</em><em>=</em><em>e</em><em>²</em><em>+</em><em>2</em><em>4</em><em>²</em>

<em>c</em><em>²</em><em>=</em><em>12.61</em><em>²</em><em>+</em><em>2</em><em>4</em><em>²</em>

<em>c</em><em>²</em><em>=</em><em>1</em><em>5</em><em>9</em><em>+</em><em>5</em><em>7</em><em>6</em>

<em>c</em><em>²</em><em>=</em><em>7</em><em>3</em><em>5</em>

<em>c</em><em>=</em><em>27.11</em>

<em> </em>

<em>I</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

3 0
3 years ago
Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?
goblinko [34]

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

A(x) = \frac{f(b)-f(a)}{b-a}

As per the statement:

f(x) = x^2-2x-4

we have to find the average rate of change from x = -1 to x = 4

At x = -1

f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1

and

at x = 4

f(4) = (4)^2-2(4)-4 = 16-8-4 = 4

Substitute these in [1] we have;

A(x) = \frac{f(4)-f(-1)}{4-(-1)}

⇒A(x) = \frac{4-(-1)}{4+1}

⇒A(x) = \frac{5}{5}

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

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