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Yanka [14]
4 years ago
6

What is the area of a parallelogram that has a base of 12 3/4 in. and a height 2 1/2

Mathematics
1 answer:
Andreas93 [3]4 years ago
5 0

i’m pretty sure it’s 31 7/8 inches. the formula is base times height.

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The sum of three consecutive even numbers is 90. What is the smallest of these numbers? number choice
Natali [406]
3 consecutive even numbers : x, x + 2, x + 4

x + x + 2 + x + 4 = 90
3x + 6 = 90
3x = 90 - 6
3x = 84
x = 84/3
x = 28...thats gonna be the smallest

x + 2 = 28 + 2 = 30
x + 4 = 28 + 4 = 32
3 0
3 years ago
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
chubhunter [2.5K]

Answer:

It's a direct variation condition,

hence ratio remains constant.

39 - 3

x - 4

x = 4×39/3 = 4×13 = 52 .. (for first blank space)

39 - 3

x - 10

x = 39×10/3 = 13×10 = 130 .. (for second blank space)

6 0
2 years ago
Read 2 more answers
Let the random variable X be equally likely to assume any of the values 1/14, 1/7, or 3/14. Determine the mean and variance of X
Dimas [21]

Answer:

1/7 ;

0.0034

Step-by-step explanation:

Given that:

X = 1/14, 1/7, 3/14

n = number of observations = 3

Since, probability of X is equally likely ;

P(X) = Σp(x) = 1 ; p(x) = 1/n = 1/3

The mean, m ;

Σx*p(x) = (1/3 * 1/14) + (1/3 * 1/7) + (1/3 * 3/14)

= 1/42 + 1/21 + 3/42

= (1 + 2 + 3) / 42

= 6 / 42

= 1/7

The variance :

Σx²*p(x) - m²

((1/3) * (1/14)^2) + ((1/3) * (1/7)^2) + ((1/3) * (3/14)^2) - (1/7)^2

= 0.0238095 - 0.0204081

= 0.0034014

= 0.0034

6 0
3 years ago
Find the arc length of the given curve between the specified points.
yuradex [85]

Answer:

4.25

Step-by-step explanation:

Given:

f(x) = \frac{x^3}{12} + \frac{1}{x} \\\\Arc Length = \int\limits^a_b {\sqrt{1 + (f'(x))^2}  } \, dx \\f '(x) = \frac{x^2}{6} - \frac{1}{x^2}\\\\f'(x)^2 = (\frac{x^2}{6} - \frac{1}{x^2})^2 = \frac{x^4}{36} +  \frac{1}{x^4} - \frac{1}{3}\\\\1 + f'(x)^2 = \frac{x^4}{36} +  \frac{1}{x^4} + \frac{2}{3}\\\\\= \frac{x^8 + 36 + 12x^4}{36x^4}\\\\= \frac{(x^4 + 6)^2}{36x^4}\\\\=\sqrt{1 + f'(x)^2}  = \sqrt{ \frac{(x^4 + 6)^2}{36x^4}}\\\\= \frac{x^2}{6} + \frac{1}{x^2} \\\\

ArcLength = \int\limits^4_1 {\frac{x^2}{6} + \frac{1}{x^2}  } \, dx \\= (\frac{x^3}{18} -  \frac{1}{x})\limits^4_1\\\\= (\frac{64}{18} - \frac{1}{4}) - (\frac{1}{18} - 1)\\\\= \frac{17}{4}= 4.25

8 0
3 years ago
caroline won $250,000 in a lottry. after paying $96,000 in taxes, she placed the remaining amount in a savings account at 2% int
BigorU [14]

Answer:

18,480

Step-by-step explanation:

you would fine how much she put in the bank in the first place!

250,000-96,000=154,000

Then you would do 154,000*0.02 to find how much interest is charged per month.

154,000*0.02=3080

Finally, you would multiply 3080 by 6 {because you need to account for all of the months}.

3080*6=18,480

5 0
3 years ago
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