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Sunny_sXe [5.5K]
3 years ago
14

Which tables display linear functions? Check all that apply. A 2-column table with 4 rows. Column 1 is labeled x with entries ne

gative 2, negative 1, 0, 1. Column 2 is labeled y with entries 1.5, 0, negative 1.5, negative 3. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is labeled y with entries 0, negative 2, negative 1, negative 3. A 2-column table with 4 rows. Column 1 is labeled x with entries 4, 5, 6, 7. Column 2 is labeled y with entries negative 2.5, negative 5.5, negative 7.5, negative 10. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 3, negative 4, negative 5, negative 6. Column 2 is labeled y with entries 6, 7, 8, 9.
Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0
I think it’s A because
babymother [125]3 years ago
5 0

Answer:6

I just took the test

Step-by-step explanation:

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Multi-Select Technology-Enhanced
larisa86 [58]

Answer:

1,6

-5,9

2,3

Step-by-step explanation:

8 0
3 years ago
Label axes according to input/output.
Andrew [12]

Answer:

height (in.) is the x-axis label

arm span (in.) is the y-axis label

The ordered pair is (30,27) is found in the scatter plot

3 0
3 years ago
Three numbers are in the ratio 1:2:3 and the sum of their cubes is 4500. Find the numbers​
kolbaska11 [484]
Let the numbers be 1k, 2k , and 3k respectively
Since the sum of their cubes is 4500,
(1k)³+(2k)³+(3k)³=4500
--> k³(36)= 4500
--> k = 5


Hence, the numbers are: 5,10 and 15 respectively

4 0
3 years ago
My first expression answer is y=5 -2x How do I plug it into x-y=1 ?? The Y
Lemur [1.5K]

Answer:

All you need to do is make sure the first expression is solved for y (which it is), and then substitute it into the second expression in place of any occurrences of y:

given the second expression:

x - y = 1

We'll replace y with it's value in the first expression:

x - (y) = 1

x - (5 - 2x) = 1

Now we can expand the resulting equation:

x - 5 + 2x = 1

So <em>neither</em> of the answers provided are correct.

You can then solve for x:

x - 5 + 2x = 1

x - 5 + 5 + 2x = 1 + 5

x + 2x = 6

3x = 6

3x/3 = 6/3

x = 2

After that, you can find y by plugging x into either of the two original equations:

y = 5 - 2x

y = 5 - 2(2)

y = 5 - 4

y = 1

8 0
3 years ago
Pls send the answer ​
luda_lava [24]

Answer:

a = \dfrac{46}{17}

b = 0

Step-by-step explanation:

\dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} =

= \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} \times \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} + \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} \times \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} - \sqrt{3}}

= \dfrac{23 + 4\sqrt{15}}{17} + \dfrac{23 - 4\sqrt{15}}{17}

= \dfrac{46}{17}

a = \dfrac{46}{17}

b = 0

4 0
2 years ago
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