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Vinvika [58]
3 years ago
5

Circle the GCF of 28x3 and 16x2y2 28x3: 2.2.7.*•*•* 16x2y2:2.2.2.2.x.x.y.y

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

Step-by-step explanation:

28x^3 = 2 * 2 * 7 * x * x * x

16x^2Y^2 = 2 * 2 * 2 * 2 * x * x * y *y

GCF = 2 * 2 * x *x = 4x^2

Circle which are in both

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