True or False? Circle your answer and justify your choice.
1 answer:
Answer:
a and c are true
Step-by-step explanation:
The question is about diagonalizability of a matrix.
a) Given that A is a 13x17 matrix over R
We get will be a square matrix 13x13.
Being a square matrix this is diagonalizable provided eigen values are independent.
True
b) A 3 × 3 matrix A with only one eigenvalue cannot be diagonalizable.
False. For a square matrix to be diagonalizable, the eigen values should be independent.
c) A matrix A of size n×n is diagonalizable if and only if A has n distinct eigenvalues. g
This is true, because for a square matrix with distinct eigen values we can see that it is diagonalizable.
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Answer:
1. A: 0.25; B: 0.03; C: 1.41; D: -0.28
2. A: 0.39; B: 0.06; C: 40.30; D: 21.81
Step-by-step explanation:
For CDF lookups, we used the Excel NORMDIST(x, mean, stdev, TRUE) function. For inverse CDF lookups, we used the NORMINV(x, mean, stdev) function.
Each of these functions works with the area under the curve from -∞ to x, so for cases where we're interested in the upper tail, we subtract the probability from 1, or subtract the x value from twice the mean.
For question 1, we computed the Z values in each case. The NORMDIST function works directly with x, mean, and standard deviation, so does not need the z value.
