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kaheart [24]
3 years ago
12

Finding solutions to linear systems

Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0
Khan academy has very good videos on how to solve them
Inessa05 [86]3 years ago
6 0
To find the solution to systems of linear equations, you can any of the methods below:

<span>1. Solve By Graphing.
2. Solve By Elimination.
3. Solve By Substitution.
4. Solve With Meta Calculator.<span>I
5. interactive System of Linear Equations.

Hope this helps.

</span></span>
You might be interested in
Max measures the diagonal of a square room to be 32feet find the perimeter and area of the room round answers to the nearest ten
Rasek [7]
Hello!

To find the side length of a square with the diagonal you use the equation

a =  \sqrt{2}  \frac{d}{2}

a is side length
d is diagonal length

Put in the values you know

a =  \sqrt{2} *  \frac{32}{2}

Divide

a =  \sqrt{2} * 16

Multiply

a = 22.6

All the sides are 22.6 feet

Add all the sides

22.6 + 22.6 + 22.6 + 22.6 = 90.4

The answer is 90.4

Hope this helps!
3 0
3 years ago
6. What number can be added to -4 to get a sum of 0?<br> a) -4<br> b) 0<br> c) %<br> d) 4
Alika [10]

-4 + x = 0

Add 4 to both sides:

x = 4

The answer is d) 4

6 0
2 years ago
Read 2 more answers
Linda is making a mosaic stepping stone to place in
Lorico [155]

Answer:

D 565.2 in

Step-by-step explanation:

First you need to find the area of the stepping stone. The rule for area of circle is pi times radius squared. To find the radius you divide 12 by 2 = 6. After you do 6 times 6= 36 you multiply 36 times pi (3.14) = 113.04. After we find the are of the stepping stone we multiply it by five to get how many inches we have to cover. 113.04 times 5= 565.2 in.

3 0
3 years ago
Can you simplify 14x+11 please??
ad-work [718]

Answer:

It cannot be further simplified

Step-by-step explanation:

11 is a prime number, so there are no numbers that can go into 14 and 11 (besides 1 and 1 would not simplify the problem)

6 0
3 years ago
Rationalize the denominators:<br> 4/√x+2
puteri [66]
\dfrac{4}{\sqrt{x}+2}=\dfrac{4}{\sqrt{x}+2}\cdot\dfrac{\sqrt{x}-2}{\sqrt{x}-2}=\dfrac{4(\sqrt{x}-2)}{(\sqrt{x})^2-2^2}=\dfrac{4\sqrt{x}-8}{x-4}\\\\Use:(a+b)(a-b)=a^2-b^2
6 0
2 years ago
Read 2 more answers
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