Ask question

Ask question

All categories

2 years ago

12

A clerk is checking the inventory of mugs there are 86 red mugs and 17 fewer blue mugs than red mugs there are 11 more green mug

s than red mugs and 8 fewer yellow mugs than blue mugs how many mugs does the clerk find in the inventory A) 122 B) 302 C)313 D)329

1 answer:

atroni [7]2 years ago

7 0

The answer is c)313

You might be interested in

What is 625 over 6561 simplified?

erastovalidia [21]

<span> the answer is 0.09526. your welcome</span>

4 0

2 years ago

Select the three expressions that are equivalent to 4/9

Deffense [45]

Answer:

8/18 or 12/27 or 16/36

Step-by-step explanation:

just add 4 on top and 9 on bottom and u should get all

6 0

3 years ago

Passes through (-4, -5), slope = 3/4

ra1l [238]

Answer:

Step-by-step explanation:

y+5 = ¾(x+4)

4 0

2 years ago

Express the trig ratios as fractions in simplest terms.

Jet001 [13]

Answer:

Step-by-step explanation:

SOH CAH TOA

cos K = 36/48 = 3/4

SIN L = 36/48 = 3/4

4 0

1 year ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

2 years ago