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Lelechka [254]
3 years ago
10

All of the In a five-choice multiple-choice test, which letter is most often the correct answer?following are tips to watch out

for when taking a test except:
SAT
2 answers:
devlian [24]3 years ago
6 0
Could you give us the multiple-choice options? Normally, letter C is the most often correct.
Rasek [7]3 years ago
6 0
Usually C., but sometimes there are different letters besides a,b,c,d,e used
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Paul had 96 fliers to post around town. Last week, he posted 16 of them. This week, he posted 38 of the remaining fliers. How ma
Solnce55 [7]
He has not posted 42 fliers.  It's simple math. 96-16=80 then 80-38=42
5 0
3 years ago
Which of these is not one of the standard placeholders on the handout master?.
Minchanka [31]

The option that is not one of the standard placeholders on the handout master is;

D: Author

The missing options are;

a. Date

b. Header

c. Page Number

d. Author

  • The Handout Master tab is the tab in Microsoft power point that is used to edit the appearance of presentation handouts which includes the headers, footers, layout and the background.

  • Now, any changes that are made to the handout master will definitely appear on all the pages of the printed copy of the handout.

  • Looking at the options, the only one that doesn't appear as a standard placeholder in handout master is Author.

Read more about handout master at; brainly.com/question/12327785

6 0
2 years ago
You should inform the person who is writing your letter of recommendation of all of the following things except.
PSYCHO15rus [73]

Answer:

d

Explanation:

6 0
2 years ago
Help?????!!!!!!!<br> Thank you
Lilit [14]
A,b, c and a because of how the forms are
8 0
3 years ago
Read 2 more answers
B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len
Citrus2011 [14]

Answer:

The additional words is 2^n

Explanation:

Given

B(n) = 2^n

Required

Determine the additional words; i.e. B(n + 1) - B(n)

From the given parameters, we have that;

B is a function of n

Such that;

B(n) = 2^n

To calculate B(n+1), we simply substitute n + 1 for n

B(n) = 2^n

B(n + 1) = 2^{n + 1}

Applying laws of indices

B(n + 1) = 2^{n} * 2^1

B(n + 1) = 2^{n} * 2

B(n + 1) = 2(2^{n})

Calculating Additional Binary Code;

B(n + 1) - B(n)

Substitute values for B(n + 1) and B(n)

B(n + 1) - B(n) = 2(2^n) - 2^n

Express 2^n as 2^ n * 1

B(n + 1) - B(n) = 2(2^n) - 2^n * 1

Express 1 as 2^0

B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0

Factorize

B(n + 1) - B(n) = 2^n(2 - 2^0)

B(n + 1) - B(n) = 2^n(2 - 1)

B(n + 1) - B(n) = 2^n(1)

B(n + 1) - B(n) = 2^n

Hence, the additional words is 2^n

8 0
3 years ago
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