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3 years ago

10

All of the In a five-choice multiple-choice test, which letter is most often the correct answer?following are tips to watch out

for when taking a test except:

2 answers:

devlian [24]3 years ago

6 0

Could you give us the multiple-choice options? Normally, letter C is the most often correct.

Rasek [7]3 years ago

6 0

Usually C., but sometimes there are different letters besides a,b,c,d,e used

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Paul had 96 fliers to post around town. Last week, he posted 16 of them. This week, he posted 38 of the remaining fliers. How ma

Solnce55 [7]

He has not posted 42 fliers. It's simple math. 96-16=80 then 80-38=42

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3 years ago

Which of these is not one of the standard placeholders on the handout master?.

Minchanka [31]

The option that is not one of the standard placeholders on the handout master is;

D: Author

The missing options are;

a. Date

b. Header

c. Page Number

d. Author

The Handout Master tab is the tab in Microsoft power point that is used to edit the appearance of presentation handouts which includes the headers, footers, layout and the background.

Now, any changes that are made to the handout master will definitely appear on all the pages of the printed copy of the handout.

Looking at the options, the only one that doesn't appear as a standard placeholder in handout master is Author.

Read more about handout master at; brainly.com/question/12327785

6 0

2 years ago

You should inform the person who is writing your letter of recommendation of all of the following things except.

PSYCHO15rus [73]

Answer:

d

Explanation:

6 0

2 years ago

Help?????!!!!!!!<br> Thank you

Lilit [14]

A,b, c and a because of how the forms are

8 0

3 years ago

Read 2 more answers

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago