When was internet created in which year

Match the following tasks with their appropriate timing.

Oliga [24]

Answer:

3. 1. 2. daily, weekly, monthly

Explanation:

8 0

3 years ago

Which one of the following media is most resistant to EMI?

natali 33 [55]

Answer:

D - Fiber-optic Cables

Explanation:

Electromagnetic interference affects cables made from different metals and can corrupt the data running through them. However, Fiber-optic cables are constructed from glass (non-metallic) and transmit pulses of light as signals to transfer data, this means that the cables are most resistant and not susceptible to EMI.

5 0

3 years ago

Write a program in Java programming language to display or calculate “Hello, Daddy and Mum”

olganol [36]

Answer:

class Simple{

public static void main(String args[]){

System.out.println("Hello Daddy and Mum);

}

Explanation:

First, we create a class, then a method and then give the Integrated Data Environment (IDE) the command to give out an output that says Hello, Daddy and Mum”

8 0

2 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago

If an if- else statement is true, it will include which kinds of results?

Salsk061 [2.6K]

In an if...else statement, if the code in the parenthesis of the if statement is true, the code inside its brackets is executed. But if the statement inside the parenthesis is false, all the code within the else statement's brackets is executed instead.

Of course, the example above isn't very useful in this case because true always evaluates to true. Here's another that's a bit more practical:

#include <stdio.h>

int main(void) {

int n = 2;

if(n == 3) { // comparing n with 3 printf("Statement is True!\n");

}

else { // if the first condition is not true, come to this block of code

printf("Statement is False!\n"); } return 0;

}

Output:

Statement is False!

5 0

3 years ago

When was internet created in which year​

When was internet created in which year