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Aleonysh [2.5K]
3 years ago
7

If the class creates a histogram of the data in the table, how many students are in the range 12 cm to 13.9 cm?

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0

Answer:

7 hope this helped

Step-by-step explanation:

muminat3 years ago
5 0

Answer:

4 i think

Step-by-step explanation:

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Darla measured the length of 4 ants in science class they were 1/2 inch 3/5 inch,1/4 inch and 3/10 inch long.What is the differe
stiks02 [169]

Convert them to have the same denominator then subtract

5 0
3 years ago
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. Whe
kherson [118]

Answer:

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}  

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)

We don't have a prior estimation for the proportion \hat p so we can use 0.5 as an approximation for this case  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
in a sale there is twenty five per cent off all prices a bed cost £33 in the sale how much was it before the sale ?
goldfiish [28.3K]
The original price was 100% and the sale was -25%
100% - 25% = 75%
This means 75% = £33
75% = 3/4
If we divide the sale amount by 3 and them multiply by 4, we will get the original amount.
£33 / 3 = £11
£11 x 4 = £44
5 0
3 years ago
What is the value of y?<br> 12<br> 13<br> х
krek1111 [17]

Answer:

y is 6.5 because it's kind of a ratio, you just need to find out what number to divide them by or multiply them by in this case, it was 13÷2 =6.5

3 0
3 years ago
What is the probability someone will randomly select a thin crust pepperoni pizza with tea to drink
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There are 18 possibilities and only one of them is a thin crust pepperoni with tea so it is 1/18
5 0
3 years ago
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