All categories

4 years ago

Find the volume length 10 2/5 cm, width 3 cm, height 8 1/3 cm

Mathematics

2 answers:

Katarina [22]4 years ago

8 0

Answer:

Step-by-step explanation:

52/5 x 3/1 x 25/3= 3900/15= 260 cm^3

AURORKA [14]4 years ago

4 0

Answer:

260 cm

Step-by-step explanation:

formula for finding volume:

l=length w=width h=height v=volume

$10\frac{2}{5}$ × 3 × $8\frac{1}{3}$

$10\frac{2}{5}$ = $\frac{52}{5}$

how did i do that?

cross multiply the whole number and the denominator together and add the product by the numerator.

$8\frac{1}{3}$ = $\frac{25}{3}$

so, $\frac{52}{5}$ × $\frac{25}{3}$ × $\frac{3}{1}$

cross simplify(dont have to do it just makes everything easier)

and you get:

$\frac{52}{1}$ × $\frac{5}{1}$ × $\frac{1}{1}$

and you get $\frac{260}{1}$

$\frac{260}{1}$ = 260 cm

plz give me a brainliesttttt

You might be interested in

The following table summarises the data from a survey on the ownership of iPods among families with different levels of income.

AURORKA [14]

The two nominal variables are related.

The following table summarises the data from a survey on the ownership of iPods among families with different levels of income.

Ownership C1 C2 C3

No 40 32 48

Yes 30 48 52

The first thing to do in order to determine if they are related or not is to state our null and alternative hypothesis

Null hypothesis

$\mathbf{H_o: Two \nomial \ variables \ are \ related}$

Alternative hypothesis

$\mathbf{H_a: Two \nomial \ variables \ are \ not \ related}$

Using the Chi-square test statistics which can be expressed by using the formula

$X ^2 = \sum \dfrac{(O-E)^2}{E}$

Ownership C1 C2 C3 Total

No 40 32 48 120

Yes 30 48 52 130

Total 70 80 100 250

The expected values are calculated as:

$\mathsf{E_{a,b} = \dfrac{(row \ total \times column \ total )}{grand \ total }}$

$\mathsf{E_{1,1} = \dfrac{(70 \times120 )}{250 }}$

$\mathsf{E_{1,1} = 33.6}$

$\mathsf{E_{1,2} = \dfrac{(70 \times130 )}{250 }}$

$\mathsf{E_{1,2} = 36.4}$

$\mathsf{E_{2,1} = \dfrac{(80 \times120 )}{250 }}$

$\mathsf{E_{2,1} = 38.4}$

$\mathsf{E_{2,2} = \dfrac{(80 \times 130 )}{250 }}$

$\mathsf{E_{2,2} = 41.6}$

$\mathsf{E_{3,1} = \dfrac{(100 \times120 )}{250 }}$

$\mathsf{E_{3,1} = 48}$

$\mathsf{E_{3,2} = \dfrac{(70 \times130 )}{250 }}$

$\mathsf{E_{3,2} = 52}$

∴ Using the Chi-square test statistics, we have:

$X ^2 = \sum \dfrac{(O-E)^2}{E}$

$X ^2 = \Bigg( \dfrac{(40-33.6)^2}{33.6}+ \dfrac{(30-36.4)^2}{36.4}+ \dfrac{(32-38.4)^2}{38.4}+ \dfrac{(48-41.6)^2}{41.6} + \dfrac{(48-48)^2}{48}+ \dfrac{(52-52)^2}{52} \Bigg)$

$X ^2 = \Bigg( \dfrac{40.96}{33.6}+ \dfrac{40.96}{36.4}+ \dfrac{40.96}{38.4}+ \dfrac{40.96}{41.6} + \dfrac{0}{48}+ \dfrac{0}{52} \Bigg)$

$X ^2 = \Bigg( 1.2190+ 1.1253+ 1.0667+ 0.9846+0+ 0 \Bigg)$

$\mathbf{X ^2 =4.3956}$

The degree of freedom df = ((r - 1) × (c - 1))

= (3 - 1) (2 -1 )

= 2 × 1

= 2

∴

Assuming the level of significance = 5%

The p-value of the Chi-square test statistics at df of 2 is:

= $\mathbf{P(X^2 > 4.3956) \implies 0.111}$

Therefore, we can conclude that since the p-value (0.111) is greater than the level of significance (0.05), we fail to reject the null hypothesis.

Hence, the two nominal variables are related.

Learn more about Chi-square test statistics here:

brainly.com/question/2365682?referrer=searchResults

7 0

3 years ago

PLEASE HELP!!!!!!!!!! What decimal is represented by this expanded form?

olga55 [171]

Answer=3610.201

3*1000=3,000
6*100=600
1*10=10
2*1/10=0.2
1*1/1000=0.001

3000+600+10+0.2+0.001=3610.201

3 0

4 years ago

I NEED HELP WITH NUMBER FIVE- NUMBER FOURS ANSWER IS 108

Nookie1986 [14]