Some proteins do indeed need assistance during the folding process. the general term used for the proteins that help other proteins fold is Chaperones.
<h3>What are Chaperones?</h3>
- Chaperones are proteins that help big proteins or macromolecular protein complexes fold or unfold conformationally. There are different groups of molecular chaperones, all of which have the same purpose: to help big proteins fold properly during or after synthesis as well as following partial denaturation.
- Protein translocation for proteolysis involves chaperones as well. The bulk of molecular chaperones aid in protein folding by binding to and stabilizing folding intermediates up until the polypeptide chain is entirely translated, rather than providing any steric information for protein folding.
- Based on their target proteins and location, chaperones have different unique modes of operation.
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The study of comparative anatomy predates the modern study of evolution. Early evolutionary scientists like Buffon and Lamarck<span> used comparative anatomy to determine relationships between species. Organisms with similar structures, they argued, must have acquired these traits from a common ancestor. Today, comparative anatomy can serve as the first line of reasoning in determining the relatedness of species. However, there are many hidden dangers that make it necessary to support evidence from comparative anatomy with evidence from other fields of study.</span>
Life would be very hard because then they may not be able to survive <span />
The tissues found within the vein if I must say are xylem and phloem. Glad I can help.
Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
