What is the measure of DG

Mathematics

1 answer:

Alecsey [184]3 years ago

7 0

M<DHG=(m arc DB)/2 Equation (1)

m<DHG=55°

Replacing in the equation (1)
55°=(m arc DB)/2

Solving for the unknown. Multiplying both sides of the equation by 2:
2(55°)=2(m arc DB)/2
110°= m arc DB
m arc DB=110°

Answer: <span>The measure of DG is 110°</span>

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How would I do this?

Lelu [443]

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R = Ron will drink a glass of milk

The format is
"If P then Q" ----> "if Q then R" so therefore "If P then R"

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3 years ago

I’m need this worked out step by step by tonight

Pie

9514 1404 393

Answer:

-3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

-7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

-14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

-9 ≤ 3x ≤ 19

Divide all parts by 3.

-3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

|(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

|f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.