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zysi [14]
3 years ago
9

Fraction that is less than 5/6 and has a denominator of 8

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0
See 5/6 is obviously more than 1/2 so 4/8 works
also 3/8 or 2/8 or 1/8

if you want all fractions then
5/6=x/8
times 24 both sides
20=3x
divide 3
6 and 2/3=x
basically x/8 such that x<6 and 2/3


examples
6/8
5/8
4/8
3/8
2/8
1/8
I would use the odd ones since the even ones simplify to non-eight denomenators
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Jack and Jill had a lemonade stand. At the end of the day they had 75 buckles and quarters totaling $6.75. How many of each type
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An equation of the line that passes through (3, 1) and (0, 10).
MrMuchimi

Answer:

So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10

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(3, 1) and (0, 10)

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3 0
3 years ago
A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the
Ne4ueva [31]

The number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

<h3>What is the rule of product in combinatorics?</h3>

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in p \times q ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

We're specified that:

  • The password needs to be 4 characters long
  • It must have 3 letters and 1 of 10 special characters.
  • Repetition is allowed.

So, each of 3 characters get 26 ways of being 1 letter. (assuming no difference is there between upper case letter and lower case letter).

And that 1 remaining character get 10 ways of being a special character.

So, by product rule, this choice (without ordering) can be done in:

26 \times 26 \times 26 \times 10 = 175760 ways.

Now, the password may look like one of those:

  1. L, L, L, S
  2. L, L, S, L
  3. L, S, L, L
  4. S, L, L, L

where S shows presence of special character and L shows presence of letter.

Those 175760 ways are available for each of those four ways.

Thus, resultant number of ways this can be done is:

175760 \times 4 = 703040

Thus, the number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

Learn more about rule of product here:

brainly.com/question/2763785

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