Ask question

Ask question

All categories

4 years ago

7

The ratio of girls girls to boys boys at a movie is 6 font size decreased by 5 : font size decreased by 5 7 6 : 7. If there are

28 28 boys boys, how many girls girls are at the movie?

1 answer:

inysia [295]4 years ago

7 0

Question:

The ratio of girls girls to boys boys at a movie is 6:7. If there are 28 boys boys, how many girls girls are at the movie?

Answer:

There are 24 girls at the movie.

Step-by-step explanation:

Given:

The ratio of girls to boys = 6:7

Number of boys = 28

To Find:

Number of Girls at the movie = ?

Solution:

The Ratio of girls to boys = 6:7

girls : boys = 6 : 7

girls : 28 = 6 : 7

$\frac{girls}{28} = \frac{6}{7}$

Now by cross multiplication

$7 \times girls = 6 \times 28$

$7 \times girls = 168$

$girls = \frac{168}{7}$

girls = 24

You might be interested in

Write an equation in slope-intercept line form form for the line perpendicular to 2x-3y=12 that passes through the point (8,5)

Alekssandra [29.7K]

Answer:

3x+2y=34

Step-by-step explanation:

L1: 2x-3y=12 => the slope m1=-2/(-3)=2/3

L2 perpendicular to L1 => m2= -1/m1= -3/2

the point A(8,5) ∈ L2

=> y–yA=m2(x–xA)

L2: y-5=-3/2 *(x-8)

L2: 2y-10=-3x+24

L2: 3x+2y=34

8 0

3 years ago

Choose the two rectangular prisms that have a volume of 36 cm”.

Lina20 [59]

Answer:

B & D

Step-by-step explanation:

Volume is calculated as:

$Volume = Length * Width * Height$

For (a):

$Length = 3cm$

$Width = 4cm$

$Height = 5cm$

$Volume = 3cm * 4cm * 5cm$

$Volume = 60cm^3$

For (b):

$Length = 3cm$

$Width = 4cm$

$Height = 3cm$

$Volume = 3cm * 4cm * 3cm$

$Volume = 36cm^3$

For (c):

$Length = 4cm$

$Width = 2cm$

$Height = 2cm$

$Volume = 4cm * 2cm * 2cm$

$Volume = 16cm^3$

For (d):

$Length = 2cm$

$Width = 3cm$

$Height = 6cm$

$Volume = 2cm * 3cm * 6cm$

$Volume = 36cm^3$

<em>There's no need to check for (e)</em>

<em>Option b and d answers the question</em>

5 0

3 years ago

I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr

Illusion [34]

Answer:

<h2><u>question 1</u></h2>

$n^{2} - 20n -96 = 0$

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u /> $x^{2} + 12 x = 48$ <u />

in the form $ax^{2} +bx +c = 0$

= $x^{2} +12x - 48$

make use of the formula :

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

replace values to make 2 equations :

1. $\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1}$ = 3.17

2. $\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1}$ = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u /> $x^{2} -14x+40=0$ <u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u /> $5b^{2} -20b-18 = 7$ <u />

in the form $ax^{2} +bx +c = 0$

this becomes $5b^{2} -20b-18-7$

= $5b^{2} -20b-25$

can simplify by 5

= $b^{2} -4b-5 =0\\$

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0

4 years ago

Read 2 more answers

Which of the following is irrational?

Pavel [41]

The correct answer is C,

7 0

3 years ago

Read 2 more answers

Find Y. Round to the nearest tenth. Z 17 ft 8 ft X 16 ft Y Y= [?]° Law of Cosines: c2 = a + b2 - 2ab cos C

ludmilkaskok [199]

Answer:

27.8

Step-by-step explanation:

6 0

3 years ago