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3 years ago

On a horizontal number line, a point is located at +15. Describe the distance and direction of the point.

Mathematics

1 answer:

Hunter-Best [27]3 years ago

7 0

It is 15 points from zero to the right

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Factor 7d+56<br> I'll give Brainless.....

Lesechka [4]

Answer: 7(d+56)=63d

Step-by-step explanation:

U add the 7 +56 and the answer is 63d plz mark brainly

7 0

3 years ago

50 Points!!

charle [14.2K]

1. $2\cdot(8-3)-6=2\cdot5-6=4$

2. $14c-6=22\implies14c=28\implies c=2$

3. $2x+18=5x\implies 3x=18\implies x=6$

4. $18-c+9c+6=24+8c$

5. $8x=-56\implies x=-7$

Hope this helps :)

3 0

3 years ago

What is the probability that you choose a red marble and then a green marble assure you replace the this marbles

IrinaK [193]

Answer:

it gives u a green marble.

Step-by-step explanation:

If I have 1 red marble replaced by a green marble then I have a green marble.

3 0

3 years ago

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

5 0

3 years ago

The Hiking Club plans to go camping in a State park where the

svetlana [45]

Answer:

0.013

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ (1−p)ⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

and p is the probability of success.

Given n = 6, p = 0.69, and r = 0 or 1:

P = ₆C₀ (0.69)⁰ (1−0.69)⁶⁻⁰ + ₆C₁ (0.69)¹ (1−0.69)⁶⁻¹

P = (1) (1) (0.31)⁶ + (6) (0.69) (0.31)⁵

P = 0.013

3 0

3 years ago