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Zielflug [23.3K]
3 years ago
15

On a horizontal number line, a point is located at +15. Describe the distance and direction of the point.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0
It is 15 points from zero to the right
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Order the following numbers from least to greatest. 180, 8, 9, 8.5, 762*
n200080 [17]

Answer:

8,8.5,9,180,762

Step-by-step explanation:

6 0
3 years ago
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Calculate the formula by using simultaneous equation <br><br>1: 2x+3y = -1 <br> x+y = -1 ​
Rina8888 [55]

I think that X = -2 and Y = 1

I hope my answer will serve you.

5 0
3 years ago
How do I solve this?
katrin [286]
This is a problem in binominal probability.  Either the rented film is a comedy or is not a comedy (binary outcomes).  the probability that the rented film is a comedy is 52%.

You must calculate and add together three probabilities to derive a final answer:

binompdf(7,0.52,0), binompdf(7,0.52,1) and binompdf(7,0.52,2).

Can you do this?  Let me know if you need further help with this problem.
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3 years ago
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}

d) Probability of at most one black ( BW or WW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}

6 0
3 years ago
Solve for b.<br><br> b+(−1.9)=−3.7<br><br> Enter your answer in the box
Luda [366]

Answer:

  • b = -1.8

Step-by-step Solution:

<u>Subtract or add to obtain your answer.</u>

  • b + (−1.9) = −3.7
  • => b - 1.9 = -3.7
  • => b = -3.7 + 1.9
  • => b = -1.8

Hence, the value of b is -1.8

5 0
2 years ago
Read 2 more answers
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