To solve this just put a 1 over the 15. So it would be 12/7 + 15/1 which is 16 5/7.
Domain is numbers you can use
we can't use numbers that cause problems
numbers that make division by zero and sqar roots of negative numbers
f(x)=√x+2
x cannot be negative
x can equal zero, that results in zero
√0=0
domain=all real numbers greater than or equal to 0
C
Jummai and Tunde will each have 9 and 6 bananas respectively.
For the given ratio case we use the sharing ratio criterion to solve the problem.
Jummai is 12 years old.
Tunde is 8 years old.
Their ages are in ratio of;
A = 12 : 8
A = 3 : 2
The ratio's sum is 5.
15 bananas total are available for sharing.
Jummai will have 
bananas 
= (15 x 3/5) = 9
Tunde will have 
bananas = (15 x 2/5) = 6
Jummai and Tunde will each have 9 and 6 bananas with them.
To learn more about Ratio click here:
brainly.com/question/13419413
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Answer:
m(m-3)=108
Step-by-step explanation:
Complete question below:
Two positive integers are 3 units apart on a number line. Their product is 108.
Which equation can be used to solve for m, the greater integer?
m(m – 3) = 108
m(m + 3) = 108
(m + 3)(m – 3) = 108
(m – 12)(m – 9) = 108
Solution
On the number line,
Let
m= larger integer
The integers are 3 numbers apart on the number line, so
m-3=smaller integer
The product (×) of the larger and smaller integers=108
(m)*(m-3)=108
m(m-3)=108
Therefore, the equation that can be used to solve for m, the larger integer is:
m(m – 3) = 108
4 tenths and the one is either in the ones place or the 100 hundredth place
