Question

Jason is a very good bowler and has proven over the

Answer 1

Answer:

The probability that Jason will get  exactly 7 strikes out of 10 attempts is 0.117.

Step-by-step explanation:

We are given that Jason is a very good bowler and has proven over the  course of a season of league play that he gets a  STRIKE 50% of the time.

Also, Jason has been given 10 attempts.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 10 attempts

            r = number of success = 7 strikes

            p = probability of success which in our question is % of the time

                   he gets a strike, i.e; p = 50%

Let X = Number of strikes Jason get

So, X ~ Binom(n = 10, p = 0.50)

Now, probability that Jason will get  exactly 7 strikes out of 10 attempts is given by = P(X = 7)

                 P(X = 7)  =  $\binom{10}{7} \times 0.50^{7} \times (1-0.50)^{10-7}$

                                =  $120 \times 0.50^{7} \times 0.50^{3}$

                                =  $120 \times 0.50^{10}$

                                =  0.117

Therefore, the probability that Jason will get  exactly 7 strikes out of 10 attempts is 0.117.