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ValentinkaMS [17]
3 years ago
14

What is the vertex, y intercept, and a value of this equation? "y=-x^2-4x-1"?

Mathematics
1 answer:
cluponka [151]3 years ago
8 0
Hello : 
y= -x²-4x-1
y = - (x²+4x+1)
y = - ((x²+4x+4)-4+1)
y = - ((x+2)²-3)
y = -(x+2)²+3     the vertex is A(-2 ; 3)
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Let $a$ and $b$ be nonzero real numbers such that
algol [13]
<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0
1 year ago
If f(x) = (2x^3 − 4)^6, then what is f '(x)?
Dominik [7]
The correct answer is:

6(2x^3-4)^5(6x^2)

Explanation:

That is the derivative after you differentiate using the Chain Rule.
4 0
2 years ago
What’s the volume of a cylinder with a radius of 1 and height of 3ft?
Dafna1 [17]

Answer:

9.42

Step-by-step explanation:

V=pir2h

(pi, radius squared, height)

hope this helped!

6 0
2 years ago
Require help with this question
user100 [1]
A) There are a number of ways to compute the determinant of a 3x3 matrix. Since k is on the bottom row, it is convenient to compute the cofactors of the numbers on the bottom row. Then the determinant is ...
  1×(2×-1 -3×1) -k×(3×-1 -2×1) +2×(3×3 -2×2) = 5 -5k

bi) Π₁ can be written using r = (x, y, z).
  Π₁ ⇒ 3x +2y +z = 4

bii) The cross product of the coefficients of λ and μ will give the normal to the plane. The dot-product of that with the constant vector will give the desired constant.
  Π₂ ⇒ ((1, 0, 2)×(1, -1, -1))•(x, y, z) = ((1, 0, 2)×(1, -1, -1))•(1, 2, 3)
  Π₂ ⇒ 2x +3y -z = 5

c) If the three planes form a sheath, the ranks of their coefficient matrix and that of the augmented matrix must be 2. That is, the determinant must be zero. The value of k that makes the determinant zero is found in part (a) to be -1.

A common approach to determining the rank of a matrix is to reduce it to row echelon form. Then the number of independent rows becomes obvious. (It is the number of non-zero rows.) This form for k=-1 is shown in the picture.

5 0
3 years ago
Compare Look at these equations. Do you think they are all linear equations? Can they
Georgia [21]

Answer:

Yes they can all be written in y = mx + b. You just have to move the terms around.

Step-by-step explanation:

y = 2x -3, this is already in slope-intercept form

Now, y - 2 = x + 2: We can add 2 on both sides to cancel out the one on the left side:

y - 2 = x + 2

y - 2 + 2 = x + + 2

y = x + 4 <-- This is in y = mx + b form

Now the last one, 3x = 9 + 3y

We can first divide all terms by 3,

3x = 9 + 3y

/3     /3   /3

x = 3 + y: Then we can subtract 3 from both sides:

x - 3 = 3 + y - 3

x - 3 = y

These are all linear equations because none of the x's have bigger powers than 1. x^2 is a quadratic equation and x^3 is cubic equation.

6 0
2 years ago
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