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3 years ago

Helppp!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

gladu [14]3 years ago

8 0

Answer:

I solved it and my answer is - 3

Leno4ka [110]3 years ago

5 0

Answer:x=-3

Step-by-step explanation:

Simplify the top 3x-15/2 = 3(x-5)/2

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The function d(x)=1375-110 represents the distance a high speed train is from its destination after x hours. How long does the t

aalyn [17]

D(x)=1375-110x
when it reaches 0 it has reached destination
0=1375-110x
add 110x to both sides
110x=1375
divide both sides by 110
x=12.5
answer is 12.5 hour

6 0

3 years ago

С<br> What is the solution to the equation 3x ÷ (-6) = -12?

Nat2105 [25]

Answer:

x=24

Step-by-step explanation:

First: Multiply -6 to both sides

Next: You get 3x=72

Then: Divide 72 by 3

Last:....

ANSWER: x=24

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3 years ago

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An element with a mass of 120 grams decays by 27.5% per minute. To the nearest tenth of a minute, how long will it be until ther

tangare [24]

Answer:

12.7

Step-by-step explanation:

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3 years ago

Which view is not correct for the figure above?

Bezzdna [24]

Answer:

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Step-by-step explanation:

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3 years ago

In parallelogram ABCD below, line AC is a diagonal, the measure of angle ABC is 40 degrees, and the measure of angle ACD is 57 d

Lorico [155]

Answer:

The measure of angle CAD is 83 degrees.

Step-by-step explanation:

Given information: ABCD is a parallelogram, AC is a diagonal, $\angle ABC=40^{\circ}$ and $\angle ACD=57^{\circ}$ .

The opposite sides of parallelogram are congruent.

The diagonal AC divides the parallelogram in two congruent triangles.

In triangle ABC and ADC,

$AB\cong CD$ (Opposite sides of parallelogram)

$\angle ABC\cong \angle ADC$ (Opposite angles of parallelogram)

$BC\cong DA$ (Opposite sides of parallelogram)

By SAS postulate,

$\triangle ABC\cong \triangle CDA$

Since we know that opposite angles of parallelogram are equal, therefore

$\angle ABC\cong \angle ADC$

$\angle ADC=40^{\circ}$

According to the angle sum property the sum of interior angles of a triangle is 180 degrees.

$\angle CAD+\angle ACD+\angle ADC=180^{\circ}$

$\angle CAD+57^{\circ}+40^{\circ}=180^{\circ}$

$\angle CAD=83^{\circ}$

Therefore the measure of angle CAD is 83 degrees.

6 0

3 years ago