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Ksenya-84 [330]
3 years ago
10

Match the range of the function f(x)=x^2x-1

Mathematics
1 answer:
natima [27]3 years ago
3 0

Appears that you've overlooked the need to share the possible answer choices.


f(x)=x^2x-1 has a parabolic graph with vertex at (0,-1). This is also the location of the vertex. Because the coefficient of x^2 is positive, this graph opens up. Thus, the smallest possible y value here is -1. The range of this function is

[-1, infinity).


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