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3 years ago

I hate orange juice popping do you what do you like

Mathematics

2 answers:

pychu [463]3 years ago

4 0

Answer:

what even is this question lol

Step-by-step explanation:

Vladimir [108]3 years ago

4 0

uh what is orange juice popping

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Please help!!!! I'll give brainlist

Ymorist [56]

Answer:

Hello! answer: y = 122

Step-by-step explanation:

360 - 116 = 244 244 ÷ 2 = 122 therefore y = 122

Hope that helps!

7 0

3 years ago

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Can I get some help ???

Nikitich [7]

Answer is D. <em><u>288</u></em> . i am glad to help

4 0

3 years ago

I need help on this problem someone please help

Hatshy [7]

The outlier is a because it is the most different value compared to the rest.

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3 years ago

Read 2 more answers

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

2 years ago

List 3 values that would make this inequality true 43 < y -30

prohojiy [21]

43 < y - 30
add 30 to both sides
73 < y

y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.

Hope this helps!

4 0

3 years ago