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Readme [11.4K]
3 years ago
5

Rounding can be useful in daily life by

Computers and Technology
1 answer:
Readme [11.4K]3 years ago
5 0
The answer is b
allowing you to add numbers in your head quickly..
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my brother

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A media file refers to what kind of file? A. Clip art
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your answer will be

<h2><em><u>C; image</u></em></h2>
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Write a program that unpickle's employee dictionary and while reading from the dictionary, it allows users to lookup an employee
melamori03 [73]

Answer:

Check the explanation

Explanation:

from Employee import *

import pickle

import random

def unpickle_employee(filename):

file=open(filename,'rb')

data=pickle.load(file)

file.close()

return data

def pickle_employee(data,filename):

file=open(filename,'wb')

pickle.dump(data,file)

file.close()

if __name__=='__main__':

filename="Employees.dat"

'''

E=Employee("Ajay",1,"R&D","Manager")

data={}

data[1]=E

pickle_employee(data,filename)

'''

data=unpickle_employee(filename)

 

while True:

print("\nData In Employee.dat")

for d in data:

print("Employe data: ",data[d].get_name(),"({},{},{})".

format(data[d].get_id_number(),data[d].get_department(),data[d].get_job_title()))

 

print("\n\n\t\tMenu")

print("To add new Employee, Enter a")

print("To update any Employee, Enter u")

print("To delete any Employee, Enter d")

print("Enter anything to quit")

choice=input("Enter: ")

if choice=='a':

id_number=random.randrange(100,200,1)

while id_number in data:

id_number+=1

if id_number>=200:

id_number=100

name=input("Enter the Name: ")

department=input("Enter the Department: ")

job_title=input("Enter the job title: ")

E=Employee(name,id_number,department,job_title)

data[id_number]=E

elif choice=='u':

id_number=int(input("Enter the Employee id_number to update: "))

for d in data:

print(id_number,d,d==id_number)

if id_number in data:

print("Employe data: ",data[id_number].get_name(),"({},{})".

format(data[id_number].get_department(),data[id_number].get_job_title()))

print("\nPlease Enter the details")

name=input("Enter the Name: ")

department=input("Enter the Department: ")

job_title=input("Enter the job title: ")

E=Employee(name,id_number,department,job_title)

data[id_number]=E    

else:

print("Employee doesn't exist\n")

elif choice=='d':

id_number=int(input("Enter the Employee id_number to delete: "))

if id_number in data:

print("Employe data: ",data[id_number].get_name(),"({},{})".

format(data[id_number].get_department(),data[id_number].get_job_title()))

choice=input("\nPlease Enter y to confirm, anything else to cancel: ")

if choice=='y':

del data[id_number]

else:

print("Employee doesn't exist\n")

else:

break

pickle_employee(data,filename)

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3 years ago
Write 5 chart types​
Lemur [1.5K]

Answer:

pie chart

line chart

area chart

bar charts

histogram

scatter plot

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3 years ago
Declare a character variable letterStart. Write a statement to read a letter from the user into letterStart, followed by stateme
oee [108]
  1. Answer: import java.util.Scanner; public class CharTestt {     public static void main(String[] args) {     System.out.println("Please enter a character ");     Scanner input = new Scanner(System.in);     char letterStart = input.next().charAt(0);     char thenextChar = (char)(letterStart+1);     System.out.print(letterStart);     System.out.println(thenextChar); } } Explanation: Import Scanner Class Prompt user to enter a character Read and save user's input in a variable char letterStart = input.next().charAt(0); Knowing that the next character using ASCII is +1, create a new character variable and add 1 print the character entered and the new character all on same line without spaces
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