Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
around 6 and a half pounds
to get an A, she needs >=160 points and she already has 125 points
let 'x' be the number of points on the last part of her project then
125 + x >= 160
x >= 160 - 125
x >= 35
Sarah needs at least 35 points on the last part of her project.
Answer:
A
Step-by-step explanation:
C and D are both wrong for the same reason. The denominator should be (x +1)*5 which means that either A or B is correct.
C and D have an error seldom seen on Brainly. It means that the denominator has been added rather than multiplied but even the addition is a little strange. Frankly, I don't know what has to be done to get either of them.
So the answer is
numerator: 5*(x + 9) + (x + 1)(x - 2)
denominator: 5*(x + 1)
Simplify the numerator. Remove the brackets.
numerator: 5x + 45 + x^2 - 2x + x - 2 Gather like terms
numerator: x^2 + 5x - 2x + x + 43 Simplify
numerator: x^2 + 4x + 43
Answer
x^2 + 4x + 43
==========
5(x + 1)
