Function of alcohol in alcohol thermometer

2 answers:

tatiyna3 years ago

7 0

Alcohol is increasingly expanding with heat. Having it go up the ladder quicker than a lot of liquids would have done. It has a low freezing point, too. It's easy to dye because of the readability. I 'm sure someone will teach you about the evaporative effects of alcohol, and why they do these things. Though that's why it's used briefly in thermometers.

Alexandra [31]3 years ago

3 0

Answer:

Fahrenheit's first thermometer contained alcohol, which has a lower freezing point than water. ... Glass bulb thermometers work because liquids, such as water, alcohol, or mercury, expand slightly when the temperature rises. If the liquid is trapped in a narrow tube, it has nowhere to go but up. I think this may help you

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Electric field lines moves away from positive to wards negative?

Archy [21]

The vector force on the unit positive charge placed at any location in the field defines the strength of the electric field at that point. The charge used to determine field intensity (field strength) is known as the test charge. Now, a field line is defined as a line to which the previously mentioned field strength vectors are tangents at the relevant places. When we study positive charge field lines, the field strength vectors point away from the positive charge. If there is a negative charge anywhere in the vicinity, the field lines that began from the positive charge will all terminate at the negative charge if the value of the negative charge is the same as the value of the positive charge. Remember that the number of field lines originating from positive charge is proportional to the charge's value, and similarly, the number of field lines terminating at negative charge is proportionate to the charge's value. As a result, if all charges are equivalent, all lines originating from the positive charge terminate at the negative charge. If the value of the positive charge is greater than the value of the negative charge, the number of lines ending at the negative charge will be proportionally less than the number of lines beginning at the positive charge. The remaining lines that do not end at the negative charge will go to infinity. If the positive charge is less, all lines from it terminate at a negative charge, and any other reasonable number of ines terminate at a negative charge from infinity. We should also keep in mind that the number of lines that run perpendicular to the field direction across a surface of unit area is proportional to the field strength at that location. As a result, lines are dense in the strong field zone and sparse in the low intensity region.

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2 years ago

Projectile effects are a hazard in __________________. magnetic resonance imaging (MRI) fields pediatric units emesis stations o

zhenek [66]

Projectile effects are a hazard in MRI fields.

<h3>What is MRI field?</h3>

MRI stands for - Magnetic resonance imaging and it is a medical imaging technique that uses a magnetic field and radio waves to create detailed images of the organs and tissues in your body.

Projectile effects are a hazard in MRI fields, due to attraction exerted by the static magnetic field of the MRI scanner on ferromagnetic objects accidentally introduced into the MRI-scanner room.

Thus, Projectile effects are a hazard in MRI fields.

Learn more about MRI fields here: brainly.com/question/23730902

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3 years ago

A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en

Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

$-\frac{dU}{dx}=F\\ dU=-Fdx$

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

$U=\frac{-7}{2}x^{2} + 11x + c$

we know that U is equal to 26 J when x is zero, so:

$U=\frac{-7}{2}x^{2} + 11x + c$

$26=\frac{-7}{2}(0)^{2} + 11(0) + c$

$26=c$

Finally, the equation for the potential energy is:

$U(x)=\frac{-7}{2}x^{2} + 11x + 26$

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

$x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}$