Question

an object falls 16t2 feet in t seconds. you drop a rock from a bridge that is 75 feet above the water. will the rock hit the water in 2 seconds?

Answer 1

Answer:

No, the rock will not hit the water in 2 second but it will hit the water in t ≅ 2.17 second

Step-by-step explanation:

Let the distance be s in feet. i.e,  $s= 16 t^2$ where t is in second.

You drop a rock from a bridge that is 75 feet above the water.

Use the  expression $s =16t^2$ to solve for t:

Given: s =75 feet

then, substitute in the above expression:

$75 = 16 t^2$ or we can write it as:

$t^2=\frac{75}{16}= 4.6875$ or

$t = \sqrt{4.6875}$

⇒ t = 2.16506351 or t ≅2.17 second

Therefore, the rock hit the water in t≅2.17 second