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Solve for x. −1/5x≥−2
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We need to solve for the height of the tree given two angles and distance between the two observers. See attached drawing for a better understanding of the problem.
We derive to equations using SOH CAH TOA such as below:
sin30 = h / x
sin 45 = h / (100-x)
sin 45 (100-x) = xsin30
70.71 - 0.71x = 0.5x
70.71 = 1.21 x
x = 58.44
Solving for h, we have:
h = xsin30
h = 58.44 sin30
h = 29.22
The height of the tree is 29.22 feet.
We derive to equations using SOH CAH TOA such as below:
sin30 = h / x
sin 45 = h / (100-x)
sin 45 (100-x) = xsin30
70.71 - 0.71x = 0.5x
70.71 = 1.21 x
x = 58.44
Solving for h, we have:
h = xsin30
h = 58.44 sin30
h = 29.22
The height of the tree is 29.22 feet.