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Goryan [66]
4 years ago
9

Solve for x. −1/5x≥−2

Mathematics
1 answer:
Rzqust [24]4 years ago
7 0

Answer:

x ≤ -10

Step-by-step explanation:

distribute -2 into your denominator (5)

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N+5/16=-1<br><br> Solve for n<br><br><br> I will reward Brainliest
Wittaler [7]

Answer:

Step-by-step explanation:

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n+\frac{5}{16}=-1

n+165​=−1

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n+\frac{5}{16}{\color{#c92786}{-\frac{5}{16}}}=-1{\color{#c92786}{-\frac{5}{16}}}

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3 0
3 years ago
1. What is the degree of the polynomial?<br> t3 + 5t2 – 3t + 2
gladu [14]
I’m assuming that the first number is supposed to be raised by the power of 3. The degree of this polynomial would be 3 then if this is the case.
7 0
3 years ago
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mack plans to meet his 4 friends. how many different ways can he make his visit if he visits each friend once?
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4 0
4 years ago
A research team conducted a study showing that approximately 25% of all businessmen who wear ties wear them so tightly that they
Sonbull [250]

Answer:A) 0.9866

Step-by-step explanation:

Probability of at least one tie is too tight is

Probability of tight tie 25/100

Probability of not a tight tie is 1-25/100=3/4

=1-(3/4)^15=0.9866

B)0.764

C)0.013

D)0.236

Method 2

This is binomial probability.

n=15 (number of businessmen

p=.25 (probability that a businessman wears the tie so tightly

A)

x = number of businessmen out of 15 who wears the tie so tightly

P( at least 1) = P( x >= 1) = 1-P(x=0)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P( at least 1) = 1- 0.013363 = 0.9866

B)

P(more than 2) = P( x > 2) = 1-P( x=0)-P(x=1)-P(x=2)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P(x=1) = 15C1 (.25)^1 (.75)^14 = 0.066817

P(x=2) = 15C2 (.25)^2 (.75)^13 = 0.155907

1-P( x=0)-P(x=1)-P(x=2) = 1 - 0.013363 - 0.066817 - 0.155907 = 0.763912

C)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

D)

P( at least 13) = P(x=13)+P(x=14)+P(x=15)

P(x=13)= 15C13 (.25)^13 (.75)^2 = 0.000001

P(x=14)= 15C14 (.25)^14 (.75)^1 = 0.000000

P(x=15)= 15C15 (.25)^15 (.75)^0 = 0.000000

P(x=13)+P(x=14)+P(x=15) = .000001+.000000+.000000 = 0.000001

4 0
4 years ago
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