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Delvig [45]
3 years ago
6

In woodshop class, you must cut several pieces of wood to within 3/16 inch of the teacher's specifications. Let (s-x) represent

the difference between the specification s and the measured length x of a cut piece.
(a)Write an absolute value inequality that describes the values of x that are within the specifications.

(b) The length of one piece of wood is specified to be s=5 1/8 inches. Describe the acceptable lengths for this piece.
Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

  (a) |s - x| ≤ 3/16

  (b) 4 15/16 ≤ x ≤ 5 5/16

Step-by-step explanation:

(a) The absolute value of the difference from spec must be no greater than than the allowed tolerance:

  |s - x| ≤ 3/16

__

(b) Put 5 1/8 for s in the above equation and solve.

  |5 1/8 - x| ≤ 3/16

  -3/16 ≤ 5 1/8 -x ≤ 3/16

  3/16 ≥ x -5 1/8 ≥ -3/16 . . . . multiply by -1 to get positive x

  5 5/16 ≥ x ≥ 4 15/16 . . . . . . add 5 1/8

Pieces may be between 4 15/16 and 5 5/16 inches in length.

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Dilate the given points distance from the origin (x,y) (0.8x, 0.8y) . The point (-10,-20) becomes & point (15,25) become
dalvyx [7]

Answer: The point (-10,-20) becomes (-8,-16) & point (15,25) becomes (12,20).

Step-by-step explanation:

When a point (x,y) is dilated by a scale factor k from the origin, then the new points become

(kx,ky).

The given rule of dilation : (x,y) →(0.8x, 0.8y)

The first point is (-10,-20), so its image will be

(-10,-20)\to (0.8\times-10,0.8\times-20)=(-8,-16)

So, the point (-10,-20)  becomes (-8,-16).

The second point is (15,25), so its image will be

(15,25)\to (0.8\times15,0.8\times25)=(12,20)

So, the point (15,25) becomes (12,20).

Hence, the point (-10,-20) becomes (-8,-16) & point (15,25) becomes (12,20).

8 0
3 years ago
Which of the following parametric equations are equivalent to the polar equation r=3 cos theta
Allushta [10]
To solve the problem you must know that to change from Cartesian to polar coordinates you must write:
 x = rcos (θ)
 Where "r" is the radius
 Likewise y = rsin (θ)
 Therefore, in the expression r = 3cos (θ) one can write r as:
 r = x / cos (θ)
 So:
 x / cos (θ) = 3cos (θ)
 x = 3cos ^ 2 (θ)
 The same for y ...
 y = rsin (θ)
 y = 3cos (θ) sin (θ).

  Finally the correct answer is option 2.
 x = 3cos ^ 2 (θ) y = 3cos (θ) sin (θ).
5 0
3 years ago
Read 2 more answers
Please help me:) thanks
nika2105 [10]

Answer:

B. Side <em>a</em> is 7 inches long and side <em>b</em> is 6 inches long.

Step-by-step explanation:

Since the scale drawing is three times bigger than the actual object, divide both numbers by three to find the object size.

Side a:

21/3 = 7 inches

Side b:

18/3 = 6 inches

6 0
3 years ago
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FACTOR the expression 6x+3y-12 using the greatest common multiple.
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

For 6x+3y-12 the greatest common factor is 3 so

3(2x+y-4)

For -2+6x+4+4x

10x+2 and 2 is greatest common factor so

2(5x+1)

8 0
3 years ago
Line p has an equation of y=-8x+6. Line q, which is perpendicular to line p, includes the point (2,–2). What is the equation of
Arturiano [62]

Answer:

y =  \frac{1}{8} x - 2  \frac{1}{4}

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is the y-intercept

Line p: y= -8x +6

slope= -8

The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.

m(-8)= -1

m= -1 ÷(-8)

m= ⅛

Substitute m= ⅛ into the equation:

y= ⅛x +c

To find the value of c, substitute a pair of coordinates that the line passes through into the equation.

When x= 2, y= -2,

-2= ⅛(2) +c

- 2 =  \frac{1}{4}  + c

c =  - 2 -  \frac{1}{4}

c =  - 2 \frac{1}{4}

Thus, the equation of line q is y =  \frac{1}{8} x - 2 \frac{1}{4}.

4 0
3 years ago
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