Let, the number = x
It would be: x * 96% = 42
x * 0.96 = 42
x = 42 / 0.96
x = 43.75
In short, Your Answer would be 43.75
Hope this helps!
Before her promotion, Mitch was receiving $40,000 per year
after tax. Since the loan payment is 4%, therefore the money that goes to the
loan is:
Loan payment = $40,000 * 0.04
Loan payment = $1,600
After her promotion, Mitch is now receiving:
New salary = $40,000
* 1.25
New salary = $50,000
Therefore the new loan payment becomes:
New loan payment = $50,000 * 0.04
New loan payment = $2,000
Therefore Mitch is paying an extra payment of:
$2,000 - $1,600 = $400
Answer: $400
Answer:
x2>y
Step-by-step explanation:
square is 2 and a number is x x2 and longer is another way for greater than another number witch is y
Answer:
Answer:
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Step-by-step explanation:
Potatoes : No Potatoes : Difference Difference (d)²
(Potatoes- No Potatoes)
29 41 -12 144
25 41 -16 256
17 37 -20 400
36 29 -7 49
41 30 11 121
25 38 -13 169
32 39 -7 49
29 10 19 361
38 29 9 81
34 55 -21 441
24 29 -5 25
27 27 0 0
<u>29 31 -2 4 </u>
<u> ∑ -64 2100 </u>
- We state our null and alternative hypotheses as
H0 : μd= 0 and Ha: μd≠0
2. The significance level alpha is set at α = 0.01
3. The test statistic under H0 is
t= d`/sd/√n
which has t distribution with n-1 degrees of freedom.
4. The critical region is t > t (0.005,12) = 3.055
5. Computations
d`= ∑d/n = -64/ 13= -4.923
sd²= ∑(di-d`)²/ n-1 = 1/n01 [ ∑di² - (∑di)²/n]
= 1/12 [2100- ( -4.923)] = 175.410
sd= √175.410 = 13.244
t = d`/sd/√n= - 4.923/13.244/√13
t= - 4.923/3.67344
t= -1.340
6. Conclusion :
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Answer:
1. a7
2.b4
Step-by-step explanation:
