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Ilya [14]
3 years ago
5

Does the table represent a exponential function x 1 2 3 4 y -1 -8 -27 -64

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

No, the given function is not an exponential function.

Step-by-step explanation:

The exponential function is defined as

f(x)=ab^x                   .... (1)

Where a is initial value and b is growth factor.

From the given table it is noticed that the value of y decreased as the value of x increased by 1. The function is in the form of

f(x)=-x^3                  .... (2)

f(1)=-(1)^3=-1

f(2)=-(2)^3=-8

f(3)=-(3)^3=-27

f(4)=-(4)^3=-64

The function (1) and (2) are not the same type of function.

The table represents the polynomial.

Therefore the required answer is no. The given function is not an exponential function.

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A direct variation function contains the points (2, 14) and (4, 28). Which equation represents the function?
IgorC [24]
Direct variation mean x =ky so y = x/k

(2,14) mean y = kx so 14 = k*2 so 14 = 7*2 so 14 = 14 
(4,28) mean y = kx so 28 = k*4 so 28 = 7*4 so 28 = 28

from these result that the 3rd choice is right sure 


6 0
3 years ago
Read 2 more answers
what is the solution of the system of equations? y = –2x 8 y = x – 4 a. (–1.33, –5.33) b. (4, 0) c. (0, 4) d. (–12, 32)
IRISSAK [1]
Y = -2x + 8 = x - 4
x + 2x = 8 + 4
3x = 12
x = 4
y = -2(4) + 8 = -8 + 8 = 0
Solution is (4, 0)
3 0
3 years ago
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6k+4k<-4k+6 solve for k
Genrish500 [490]

Answer:

k < 3/7

Step-by-step explanation:

Step 1:Sinplify both sides of the inequality

10k <-4k+6

Step 2: Add 4k to both sides

10k + 4k < -4k + 6 + 4k

14k < 6

Step 3:Divide both sides by 14

14k/14 < 6/14

k <3/7

Note:Provided by Mathpapa an Algebra caculator

6 0
2 years ago
Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3
polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256

#learnwithBrainly

8 0
3 years ago
What is the area of this triangle? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundre
nika2105 [10]

Answer:

Area of the triangle \simeq 5.9 sq. ft. .

Step-by-step explanation:

Length of two sides of the triangle are, 2.7 feet and 3.4 feet and the angle between them is 40° .

So, the area of the triangle is given by,

2.7 \times 3.4 \times \sin {40^{\circ}}  sq. ft.

\simeq 5.9 sq. ft.

6 0
3 years ago
Read 2 more answers
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