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3 years ago

write an equation for the line that is parallel to the given line and passes through the given point y=3x+4;(6.8)

Mathematics

2 answers:

juin [17]3 years ago

4 0

The answer to your question is y=3x-10

Troyanec [42]3 years ago

4 0

We know that two lines are parallel if they have the same slope, so we can you the equation y = 3x+b because the lines are parallel and 3 represents the slope.

y = 3x+b (6,8)

We can substitute the points in the equation

8 = 3*6 + b

I put 8 in y slot because 8 is the point on the y-axis and I put 6 in the x slot because it is the point on the x-axis

8 = 3*6 + b

8 = 18+b
-18 -18

-10 = b

The equation is

y = 3x -18

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Which points are 4 units apart?

xz_007 [3.2K]

The points that are 4 units apart are B and D

<h3>Complete question</h3>

Which points are 4 units apart? On a coordinate plane, point A is at (-2, 4), point B is at (3, -6), point C is at (-1, 0), point D is at (3, -2).

B and C

C and D

A and C

B and D

<h3>How to determine the points?</h3>

To do this, we simply calculate the distance using the following equation

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2$

Using the given points, we have:

$BC = \sqrt{(3+ 1)^2 + (-6 -0)^2} = 7.2$

$CD = \sqrt{(-1 - 3)^2 + (0 +2)^2} = 4.5$

$AC = \sqrt{(-2 + 1)^2 + (4 -0)^2} = 4.1$

$BD = \sqrt{(3 - 3)^2 + (-6 +2)^2} = 4$

Hence, the points that are 4 units apart are B and D

Read more about distance at:brainly.com/question/15821277

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