Active transport. it's the only method of transfer of material that is again concentration gradient
The complementary DNA strand would be TAGCCATGT.
I believe the appropriate dose will be 1.5 mL,
Epinephrine is used for both allergic reaction and heart attacks, in an effort to increase blood flow through veins and to reduce swelling in airways. When epinephrine is recognized by receptors on smooth muscles, it causes airway-blocking muscle constriction to subside. Other drugs that may be administered by the endotracheal route include atropine sulfate, lidocaine hydrochloride, naloxone hydrochloride, and metaraminol bitartrate.
Answer:
The regulation of the cell cycle helps in wound healing as well as replacing the lost cells by division. Thus, options B and C are correct.
Explanation:
The cell cycle can be described as the process of division and reproduction. The events result in the formation of multiple cells that have been able to deal with the repair mechanism of the body.
With the regulation of the cell cycle, the division process of the cell has been initiated and helps in the formation of multiple cells. The formed daughter cells have been able to heal the wounds effectively by accumulating and removing the dead cell.
The cell cycle has also been responsible for the replacement of lost cells, with the formation of new cells. Thus, options B and C are correct.
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
