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Juliette [100K]
3 years ago
13

Please solve for a need help

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

The two lines with arrows are parallel, which means angles A and B are supplementary.

So we have

A + B = 180º

(6<em>x</em> - 35)º + (3<em>x</em> + 53)º = 180º

(9<em>x</em> + 18)º = 180º

(9<em>x</em>)º = 162º

<em>x</em> = 18

This means angle A has measure

A = (6<em>x</em> - 35)º = 73º

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a fuel mixture consists of 3 parts oil and 11 parts gasoline. the oil costs $0.75 per liter, and the gasoline costs $1.60 per li
kupik [55]

Answer:

Total selling price= $663.82

Selling price per liter= $1.69

Step-by-step explanation:

Giving the following information:

Proportion of oil and gasoline:

Oil= 3/14= 0.21

Gasoline= 11/14= 0.79

The oil costs $0.75 per liter.

The gasoline costs $1.60 per liter.

<u>First, we need to calculate the number of liters of oil and gasoline required:</u>

<u></u>

Oil= 0.21*392= 82.32 liters

Gasoline= 0.79*392= 309.68

<u>Now, the total cost to produce 392 liters:</u>

Total cost= 82.32*0.75 + 309.68*1.6

Total cost= $577.23

<u>Finally, the total and unitary selling price:</u>

Total selling price= 577.23*1.15= $663.82

Selling price per liter= 663.82 / 392= $1.69

6 0
3 years ago
A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo
wel

The side lengths of the pool 10 ft and 45 ft.

<u>SOLUTION: </u>

Given, a rectangle swimming pool is 8 feet deep.  

One side of the pool is 4.5 times longer than the other.  

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,  

\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}

On taking square root on both sides we get,

\begin{array}{l}{\rightarrow\sqrt{n^{2}}=\sqrt{100}} \\\\ {\rightarrow n=10 \mathrm{ft}}\end{array}

So, the width will be 4.5 n=4.5 \times 10=45 \mathrm{ft}

5 0
3 years ago
Write the equation of the circle that is tangent to the y-axis.<br> Its center is at (-3,5).
abruzzese [7]

Answer:

¿De que manera usted se informa a la hora de elegir un candidato presidencial? ENTRAR AL LINK es una encuesta de 1 pregunta ,GRACIAS

https://forms.gle/VqfekaGgk8cfJhPW9

Step-by-step explanation:

5 0
2 years ago
Need Help on this assignment ASAP!
allsm [11]
The answer is y=(1/2)x -5

You are given the slope and a core donate pair so you plug them in to the equation. 2=x. -4=y. And (1/2)= m

Then work out like a one step equation

7 0
3 years ago
100 pints help would be greatly appreciated
Veronika [31]

Answer:

  (4, -2)  (see attached)

Step-by-step explanation:

Vector addition on a graph is accomplished by placing the tail of one vector on the nose of the one it is being added to. The negative of a vector is in the direction opposite to the original.

__

<h3>vector components</h3>

The components of the vectors are ...

  u  = (1, -2)

  v = (-6, -6)

Then the components of the vector sum are ...

  2u -1/3v = 2(1, -2) -1/3(-6, -6) = (2 +6/3, -4 +6/3)

  2u -1/3v = (4, -2)

<h3>graphically</h3>

The sum is shown graphically in the attachment. Vector u is added to itself by putting a copy at the end of the original. Then the nose of the second vector is at 2u.

One-third of vector v is subtracted by adding a vector to 2u that is 1/3 the length of v, and in the opposite direction. The nose of this added vector is the resultant: 2u-1/3v.

The resultant is in red in the attachment.

5 0
2 years ago
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