Answer:
D(4,-3)
Step-by-step explanation:
Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)
Let the coordinate of the fourth vertex be D(x,y).
We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.
The diagonals are BD and AC
Midpoint of BD = Midpoint of AC

The coordinates of the fourth vertex is D(4,-3)
Minus
The quadratic equation is
( -b+-SQRT(b^2 - 4ac) )/2a
Pretty sure that you got it right..
Answer:

Step-by-step explanation:
Look at graph above⤴⤴⤴
Hope this helps :)