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4 years ago

Which description describes this equation? 7x-2=33

Mathematics

1 answer:

expeople1 [14]4 years ago

7 0

Answer:

the answer is two less than seven times a number equals thirty three

Step-by-step explanation:

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Dentify the terms and like terms in the expression<br> 1/2 s - 4 + 3/4 s + 1/8 - s*3

Aleonysh [2.5K]

Your answer well be-(3*s)+(5/(4*s))-((31/8)) did this help

8 0

4 years ago

For which values of x is the expression undefined?

lord [1]

Answer:

-3, -6

Step-by-step explanation:

Any number of x that makes the bottom 0 makes the expression undefined.

Factor the polynomial in the denominator:

(x+3)(x+6)

Values of x that makes the expression undefined are -3 and -6

Support me by choosing my answer as the brainiest :)

5 0

2 years ago

A triangle with an area of 45.5 cm2 has a base

FromTheMoon [43]

If you know the base and area of the triangle, you can divide the base by 2, then divide that by the area to find the height

Step 1. 14 ÷ 2 = 7

Step 2. 45.5 ÷ 7 = 6.5

Height = 6.5 cm

3 0

3 years ago

Apply the distributive property to create an equivalent expression 1/3(3j+6) what the answer

Anna71 [15]

Answer:

$\large\boxed{\dfrac{1}{3}(3j+6)=j+2}$

Step-by-step explanation:

The distributive property: <em>a(b + c) = ab + ac</em>.

$\dfrac{1}{3}(3j+6)=\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)(3\!\!\!\!\diagup^1j)+\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)(6\!\!\!\!\diagup^2)=1j+(1)(2)=j+2$

6 0

4 years ago

Read 2 more answers

The ornament below is composed of two congruent square pyramids. Each square pyramid has base side lengths of 2 inches and a hei

kondor19780726 [428]

Answer:

The volume of the ornament is $6\frac{2}{3}\ in^{3}$

Step-by-step explanation:

we know that

The volume of the ornament is equal to the sum of the volume of the two congruent square pyramids

$V=2[\frac{1}{3}b^{2} h]$

we have

$b=2\ in$

$h=2.5\ in$

substitute

$V=2[\frac{1}{3}(2)^{2} (2.5)]$

$V=\frac{20}{3}\ in^{3}$

Convert to mixed number

$\frac{20}{3}=\frac{18}{3}+\frac{2}{3}=6\frac{2}{3}\ in^{3}$

5 0

3 years ago